Base | Representation |
---|---|
bin | 1000011100010100010… |
… | …0000111111010010111 |
3 | 111212101002120011102021 |
4 | 2013011010013322113 |
5 | 4334020232111203 |
6 | 150344104554011 |
7 | 13323141423121 |
oct | 2070504077227 |
9 | 455332504367 |
10 | 145040113303 |
11 | 565693a9938 |
12 | 24139782907 |
13 | 108a5b26b67 |
14 | 703cb72211 |
15 | 3b8d44d5bd |
hex | 21c5107e97 |
145040113303 has 2 divisors, whose sum is σ = 145040113304. Its totient is φ = 145040113302.
The previous prime is 145040113301. The next prime is 145040113343. The reversal of 145040113303 is 303311040541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145040113303 - 21 = 145040113301 is a prime.
Together with 145040113301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145040113301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72520056651 + 72520056652.
It is an arithmetic number, because the mean of its divisors is an integer number (72520056652).
Almost surely, 2145040113303 is an apocalyptic number.
145040113303 is a deficient number, since it is larger than the sum of its proper divisors (1).
145040113303 is an equidigital number, since it uses as much as digits as its factorization.
145040113303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 145040113303 its reverse (303311040541), we get a palindrome (448351153844).
The spelling of 145040113303 in words is "one hundred forty-five billion, forty million, one hundred thirteen thousand, three hundred three".
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