Base | Representation |
---|---|
bin | 1000011100100101001… |
… | …0011011011011000111 |
3 | 111212120000220011102021 |
4 | 2013021102123123013 |
5 | 4334141402101403 |
6 | 150355115424011 |
7 | 13324661624416 |
oct | 2071122333307 |
9 | 455500804367 |
10 | 145110972103 |
11 | 565a53a7129 |
12 | 24159455007 |
13 | 108b7706546 |
14 | 704833947d |
15 | 3b947988bd |
hex | 21c949b6c7 |
145110972103 has 2 divisors, whose sum is σ = 145110972104. Its totient is φ = 145110972102.
The previous prime is 145110972049. The next prime is 145110972119. The reversal of 145110972103 is 301279011541.
It is a happy number.
145110972103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 145110972103 - 237 = 7672018631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145110972173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72555486051 + 72555486052.
It is an arithmetic number, because the mean of its divisors is an integer number (72555486052).
Almost surely, 2145110972103 is an apocalyptic number.
145110972103 is a deficient number, since it is larger than the sum of its proper divisors (1).
145110972103 is an equidigital number, since it uses as much as digits as its factorization.
145110972103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 34.
Adding to 145110972103 its reverse (301279011541), we get a palindrome (446389983644).
The spelling of 145110972103 in words is "one hundred forty-five billion, one hundred ten million, nine hundred seventy-two thousand, one hundred three".
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