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14513312453 is a prime number
BaseRepresentation
bin11011000010000111…
…11001001011000101
31101110110100122212212
431201003321023011
5214210401444303
610400050353205
71022440056203
oct154103711305
941413318785
1014513312453
116178428502
12299058b805
1314a3a75463
149b9736073
1559e22aad8
hex3610f92c5

14513312453 has 2 divisors, whose sum is σ = 14513312454. Its totient is φ = 14513312452.

The previous prime is 14513312447. The next prime is 14513312459. The reversal of 14513312453 is 35421331541.

It is a balanced prime because it is at equal distance from previous prime (14513312447) and next prime (14513312459).

It can be written as a sum of positive squares in only one way, i.e., 14388722209 + 124590244 = 119953^2 + 11162^2 .

It is an emirp because it is prime and its reverse (35421331541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14513312453 - 210 = 14513311429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14513312459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7256656226 + 7256656227.

It is an arithmetic number, because the mean of its divisors is an integer number (7256656227).

Almost surely, 214513312453 is an apocalyptic number.

It is an amenable number.

14513312453 is a deficient number, since it is larger than the sum of its proper divisors (1).

14513312453 is an equidigital number, since it uses as much as digits as its factorization.

14513312453 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21600, while the sum is 32.

Adding to 14513312453 its reverse (35421331541), we get a palindrome (49934643994).

The spelling of 14513312453 in words is "fourteen billion, five hundred thirteen million, three hundred twelve thousand, four hundred fifty-three".