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145203213544031 is a prime number
BaseRepresentation
bin100001000000111111000001…
…111101101010101001011111
3201001010021212121111022012002
4201000333001331222221133
5123013002140131402111
61232453234015032515
742404404664465246
oct4100770175525137
9631107777438162
10145203213544031
11422a2378673115
121435143250b73b
1363037b17c5376
1427bdc3186795d
1511bc10735863b
hex840fc1f6aa5f

145203213544031 has 2 divisors, whose sum is σ = 145203213544032. Its totient is φ = 145203213544030.

The previous prime is 145203213544009. The next prime is 145203213544033. The reversal of 145203213544031 is 130445312302541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145203213544031 - 26 = 145203213543967 is a prime.

It is a super-2 number, since 2×1452032135440312 (a number of 29 digits) contains 22 as substring.

Together with 145203213544033, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145203213544033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72601606772015 + 72601606772016.

It is an arithmetic number, because the mean of its divisors is an integer number (72601606772016).

Almost surely, 2145203213544031 is an apocalyptic number.

145203213544031 is a deficient number, since it is larger than the sum of its proper divisors (1).

145203213544031 is an equidigital number, since it uses as much as digits as its factorization.

145203213544031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 145203213544031 its reverse (130445312302541), we get a palindrome (275648525846572).

The spelling of 145203213544031 in words is "one hundred forty-five trillion, two hundred three billion, two hundred thirteen million, five hundred forty-four thousand, thirty-one".