14532144301 has 2 divisors, whose sum is σ = 14532144302. Its totient is φ = 14532144300.

The previous prime is 14532144299. The next prime is 14532144307. The reversal of 14532144301 is 10344123541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11831783076 + 2700361225 = 108774^2 + 51965^2 .

It is an emirp because it is prime and its reverse (10344123541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14532144301 - 2¹ = 14532144299 is a prime.

It is a super-2 number, since 2×14532144301² (a number of 21 digits) contains 22 as substring.

Together with 14532144299, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 14532144301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14532144307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7266072150 + 7266072151.

It is an arithmetic number, because the mean of its divisors is an integer number (7266072151).

Almost surely, 2^14532144301 is an apocalyptic number.

It is an amenable number.

14532144301 is a deficient number, since it is larger than the sum of its proper divisors (1).

14532144301 is an equidigital number, since it uses as much as digits as its factorization.

14532144301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 14532144301 its reverse (10344123541), we get a palindrome (24876267842).

The spelling of 14532144301 in words is "fourteen billion, five hundred thirty-two million, one hundred forty-four thousand, three hundred one".