14532144307 has 2 divisors, whose sum is σ = 14532144308. Its totient is φ = 14532144306.

The previous prime is 14532144301. The next prime is 14532144313. The reversal of 14532144307 is 70344123541.

It is a balanced prime because it is at equal distance from previous prime (14532144301) and next prime (14532144313).

It is an emirp because it is prime and its reverse (70344123541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14532144307 - 2³ = 14532144299 is a prime.

It is a super-2 number, since 2×14532144307² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14532144301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7266072153 + 7266072154.

It is an arithmetic number, because the mean of its divisors is an integer number (7266072154).

Almost surely, 2^14532144307 is an apocalyptic number.

14532144307 is a deficient number, since it is larger than the sum of its proper divisors (1).

14532144307 is an equidigital number, since it uses as much as digits as its factorization.

14532144307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 34.

Adding to 14532144307 its reverse (70344123541), we get a palindrome (84876267848).

The spelling of 14532144307 in words is "fourteen billion, five hundred thirty-two million, one hundred forty-four thousand, three hundred seven".