Base | Representation |
---|---|
bin | 11011000100100110… |
… | …01101000100100010 |
3 | 1101111220110221121100 |
4 | 31202103031010202 |
5 | 214231212301310 |
6 | 10402112135230 |
7 | 1023111561045 |
oct | 154223150442 |
9 | 41456427540 |
10 | 14534103330 |
11 | 6189138a4a |
12 | 2997537516 |
13 | 14a8174856 |
14 | 9bc3c8c5c |
15 | 5a0e85ec0 |
hex | 3624cd122 |
14534103330 has 24 divisors (see below), whose sum is σ = 37788668892. Its totient is φ = 3875760864.
The previous prime is 14534103323. The next prime is 14534103347. The reversal of 14534103330 is 3330143541.
It can be written as a sum of positive squares in 2 ways, for example, as 13597192449 + 936910881 = 116607^2 + 30609^2 .
It is a super-2 number, since 2×145341033302 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14534103294 and 14534103303.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 80744929 + ... + 80745108.
Almost surely, 214534103330 is an apocalyptic number.
14534103330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14534103330 is an abundant number, since it is smaller than the sum of its proper divisors (23254565562).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14534103330 is a wasteful number, since it uses less digits than its factorization.
14534103330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161490050 (or 161490047 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 27.
Adding to 14534103330 its reverse (3330143541), we get a palindrome (17864246871).
The spelling of 14534103330 in words is "fourteen billion, five hundred thirty-four million, one hundred three thousand, three hundred thirty".
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