Base | Representation |
---|---|
bin | 1101011000011000011111… |
… | …1011110011001010010101 |
3 | 1221002111122110101200210022 |
4 | 3112012013323303022111 |
5 | 3412022242124322023 |
6 | 51142503233034525 |
7 | 3045642355051334 |
oct | 326060773631225 |
9 | 57074573350708 |
10 | 14712543589013 |
11 | 4762611334376 |
12 | 17974810b5a45 |
13 | 82950505caba |
14 | 38c13b651d1b |
15 | 1a7a912ee7c8 |
hex | d6187ef3295 |
14712543589013 has 2 divisors, whose sum is σ = 14712543589014. Its totient is φ = 14712543589012.
The previous prime is 14712543588997. The next prime is 14712543589049. The reversal of 14712543589013 is 31098534521741.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12341014428484 + 2371529160529 = 3512978^2 + 1539977^2 .
It is a cyclic number.
It is not a de Polignac number, because 14712543589013 - 24 = 14712543588997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14712543582013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7356271794506 + 7356271794507.
It is an arithmetic number, because the mean of its divisors is an integer number (7356271794507).
Almost surely, 214712543589013 is an apocalyptic number.
It is an amenable number.
14712543589013 is a deficient number, since it is larger than the sum of its proper divisors (1).
14712543589013 is an equidigital number, since it uses as much as digits as its factorization.
14712543589013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 53.
The spelling of 14712543589013 in words is "fourteen trillion, seven hundred twelve billion, five hundred forty-three million, five hundred eighty-nine thousand, thirteen".
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