Base | Representation |
---|---|
bin | 1101011010000001000100… |
… | …0000010011011011000111 |
3 | 1221012012002200001011101101 |
4 | 3112200101000103123013 |
5 | 3413002233420131403 |
6 | 51203424423040531 |
7 | 3050655063414601 |
oct | 326402100233307 |
9 | 57165080034341 |
10 | 14740613052103 |
11 | 4773505865454 |
12 | 17a09b55a0147 |
13 | 82c05948bb63 |
14 | 38d641524171 |
15 | 1a86856d771d |
hex | d68110136c7 |
14740613052103 has 2 divisors, whose sum is σ = 14740613052104. Its totient is φ = 14740613052102.
The previous prime is 14740613052101. The next prime is 14740613052163. The reversal of 14740613052103 is 30125031604741.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14740613052103 - 21 = 14740613052101 is a prime.
Together with 14740613052101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14740613052101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7370306526051 + 7370306526052.
It is an arithmetic number, because the mean of its divisors is an integer number (7370306526052).
Almost surely, 214740613052103 is an apocalyptic number.
14740613052103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14740613052103 is an equidigital number, since it uses as much as digits as its factorization.
14740613052103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 14740613052103 its reverse (30125031604741), we get a palindrome (44865644656844).
The spelling of 14740613052103 in words is "fourteen trillion, seven hundred forty billion, six hundred thirteen million, fifty-two thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •