Base | Representation |
---|---|
bin | 10101100011001111001… |
… | …111111001111110110111 |
3 | 12020120120122210122112122 |
4 | 111203033033321332313 |
5 | 143230434111200231 |
6 | 3052200452110155 |
7 | 211665134425241 |
oct | 25431717717667 |
9 | 5216518718478 |
10 | 1480945803191 |
11 | 52107a3302a8 |
12 | 1bb02590535b |
13 | a986398143a |
14 | 5196cc25091 |
15 | 287c96a677b |
hex | 158cf3f9fb7 |
1480945803191 has 2 divisors, whose sum is σ = 1480945803192. Its totient is φ = 1480945803190.
The previous prime is 1480945803151. The next prime is 1480945803193. The reversal of 1480945803191 is 1913085490841.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1480945803191 is a prime.
It is a super-2 number, since 2×14809458031912 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 1480945803193, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1480945803193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 740472901595 + 740472901596.
It is an arithmetic number, because the mean of its divisors is an integer number (740472901596).
Almost surely, 21480945803191 is an apocalyptic number.
1480945803191 is a deficient number, since it is larger than the sum of its proper divisors (1).
1480945803191 is an equidigital number, since it uses as much as digits as its factorization.
1480945803191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 53.
The spelling of 1480945803191 in words is "one trillion, four hundred eighty billion, nine hundred forty-five million, eight hundred three thousand, one hundred ninety-one".
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