Base | Representation |
---|---|
bin | 10101101110001000110… |
… | …111001000111100100101 |
3 | 12021200210022221200100101 |
4 | 111232020313020330211 |
5 | 143423421322321103 |
6 | 3101414105344101 |
7 | 212561153011234 |
oct | 25561067107445 |
9 | 5250708850311 |
10 | 1492649807653 |
11 | 5260359a3064 |
12 | 201351498031 |
13 | aa9aa6baa74 |
14 | 5235d3d2b1b |
15 | 28c61e59a1d |
hex | 15b88dc8f25 |
1492649807653 has 2 divisors, whose sum is σ = 1492649807654. Its totient is φ = 1492649807652.
The previous prime is 1492649807651. The next prime is 1492649807657. The reversal of 1492649807653 is 3567089462941.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1146884639329 + 345765168324 = 1070927^2 + 588018^2 .
It is a cyclic number.
It is not a de Polignac number, because 1492649807653 - 21 = 1492649807651 is a prime.
Together with 1492649807651, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1492649807651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 746324903826 + 746324903827.
It is an arithmetic number, because the mean of its divisors is an integer number (746324903827).
It is a 1-persistent number, because it is pandigital, but 2⋅1492649807653 = 2985299615306 is not.
Almost surely, 21492649807653 is an apocalyptic number.
It is an amenable number.
1492649807653 is a deficient number, since it is larger than the sum of its proper divisors (1).
1492649807653 is an equidigital number, since it uses as much as digits as its factorization.
1492649807653 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 78382080, while the sum is 64.
The spelling of 1492649807653 in words is "one trillion, four hundred ninety-two billion, six hundred forty-nine million, eight hundred seven thousand, six hundred fifty-three".
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