1500125119 has 2 divisors, whose sum is σ = 1500125120. Its totient is φ = 1500125118.

The previous prime is 1500125089. The next prime is 1500125131. The reversal of 1500125119 is 9115210051.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (9115210051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1500125119 - 2¹³ = 1500116927 is a prime.

It is a super-2 number, since 2×1500125119² = 4500750745309528322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1500125093 and 1500125102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1500125819) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750062559 + 750062560.

It is an arithmetic number, because the mean of its divisors is an integer number (750062560).

Almost surely, 2^1500125119 is an apocalyptic number.

1500125119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1500125119 is an equidigital number, since it uses as much as digits as its factorization.

1500125119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 25.

The square root of 1500125119 is about 38731.4487077362. The cubic root of 1500125119 is about 1144.7460695576.

The spelling of 1500125119 in words is "one billion, five hundred million, one hundred twenty-five thousand, one hundred nineteen".