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1500130005037 is a prime number
BaseRepresentation
bin10101110101000110101…
…101110101000000101101
312022102002122021002002221
4111311012231311000231
5144034231240130122
63105052240115341
7213244422436666
oct25650655650055
95272078232087
101500130005037
11529224309074
1220289a605b51
13ab600334471
145286ca2c36d
152904d9c96c7
hex15d46b7502d

1500130005037 has 2 divisors, whose sum is σ = 1500130005038. Its totient is φ = 1500130005036.

The previous prime is 1500130005013. The next prime is 1500130005061. The reversal of 1500130005037 is 7305000310051.

It is a balanced prime because it is at equal distance from previous prime (1500130005013) and next prime (1500130005061).

It can be written as a sum of positive squares in only one way, i.e., 1406629208196 + 93500796841 = 1186014^2 + 305779^2 .

It is a cyclic number.

It is not a de Polignac number, because 1500130005037 - 219 = 1500129480749 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1500130105037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 750065002518 + 750065002519.

It is an arithmetic number, because the mean of its divisors is an integer number (750065002519).

Almost surely, 21500130005037 is an apocalyptic number.

It is an amenable number.

1500130005037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1500130005037 is an equidigital number, since it uses as much as digits as its factorization.

1500130005037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1575, while the sum is 25.

Adding to 1500130005037 its reverse (7305000310051), we get a palindrome (8805130315088).

The spelling of 1500130005037 in words is "one trillion, five hundred billion, one hundred thirty million, five thousand, thirty-seven".