Base | Representation |
---|---|
bin | 1000101111101100100… |
… | …1010111101010100111 |
3 | 112100210122122000011012 |
4 | 2023323021113222213 |
5 | 4430144030104021 |
6 | 153004224332435 |
7 | 13566101355113 |
oct | 2137311275247 |
9 | 470718560135 |
10 | 150242425511 |
11 | 58798a29012 |
12 | 2514ba7411b |
13 | 1122486c2c9 |
14 | 73b3a58743 |
15 | 3d9501935b |
hex | 22fb257aa7 |
150242425511 has 2 divisors, whose sum is σ = 150242425512. Its totient is φ = 150242425510.
The previous prime is 150242425493. The next prime is 150242425513. The reversal of 150242425511 is 115524242051.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 150242425511 - 210 = 150242424487 is a prime.
It is a super-2 number, since 2×1502424255112 (a number of 23 digits) contains 22 as substring.
Together with 150242425513, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150242425513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75121212755 + 75121212756.
It is an arithmetic number, because the mean of its divisors is an integer number (75121212756).
Almost surely, 2150242425511 is an apocalyptic number.
150242425511 is a deficient number, since it is larger than the sum of its proper divisors (1).
150242425511 is an equidigital number, since it uses as much as digits as its factorization.
150242425511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16000, while the sum is 32.
Adding to 150242425511 its reverse (115524242051), we get a palindrome (265766667562).
The spelling of 150242425511 in words is "one hundred fifty billion, two hundred forty-two million, four hundred twenty-five thousand, five hundred eleven".
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