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150242425511 is a prime number
BaseRepresentation
bin1000101111101100100…
…1010111101010100111
3112100210122122000011012
42023323021113222213
54430144030104021
6153004224332435
713566101355113
oct2137311275247
9470718560135
10150242425511
1158798a29012
122514ba7411b
131122486c2c9
1473b3a58743
153d9501935b
hex22fb257aa7

150242425511 has 2 divisors, whose sum is σ = 150242425512. Its totient is φ = 150242425510.

The previous prime is 150242425493. The next prime is 150242425513. The reversal of 150242425511 is 115524242051.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 150242425511 - 210 = 150242424487 is a prime.

It is a super-2 number, since 2×1502424255112 (a number of 23 digits) contains 22 as substring.

Together with 150242425513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150242425513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75121212755 + 75121212756.

It is an arithmetic number, because the mean of its divisors is an integer number (75121212756).

Almost surely, 2150242425511 is an apocalyptic number.

150242425511 is a deficient number, since it is larger than the sum of its proper divisors (1).

150242425511 is an equidigital number, since it uses as much as digits as its factorization.

150242425511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16000, while the sum is 32.

Adding to 150242425511 its reverse (115524242051), we get a palindrome (265766667562).

The spelling of 150242425511 in words is "one hundred fifty billion, two hundred forty-two million, four hundred twenty-five thousand, five hundred eleven".