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15113001132020 = 225112310972722661
BaseRepresentation
bin1101101111101100010100…
…0100000101111111110100
31222111210022000220122210102
43123323011010011333310
53440102411242211040
652050452240013232
73116610154026101
oct333730504057764
958453260818712
1015113001132020
1148a742a164590
121841001601218
138581c440923c
143a368a4b7aa8
151b31cce76515
hexdbec5105ff4

15113001132020 has 96 divisors (see below), whose sum is σ = 36160784868096. Its totient is φ = 5251902233600.

The previous prime is 15113001131927. The next prime is 15113001132029. The reversal of 15113001132020 is 2023110031151.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 15113001131983 and 15113001132001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15113001132029) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4189490 + ... + 6912150.

It is an arithmetic number, because the mean of its divisors is an integer number (376674842376).

Almost surely, 215113001132020 is an apocalyptic number.

15113001132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 15113001132020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18080392434048).

15113001132020 is an abundant number, since it is smaller than the sum of its proper divisors (21047783736076).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

15113001132020 is a wasteful number, since it uses less digits than its factorization.

15113001132020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2723801 (or 2723799 counting only the distinct ones).

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 15113001132020 its reverse (2023110031151), we get a palindrome (17136111163171).

The spelling of 15113001132020 in words is "fifteen trillion, one hundred thirteen billion, one million, one hundred thirty-two thousand, twenty".

Divisors: 1 2 4 5 10 11 20 22 23 44 46 55 92 110 115 220 230 253 460 506 1012 1097 1265 2194 2530 4388 5060 5485 10970 12067 21940 24134 25231 48268 50462 60335 100924 120670 126155 241340 252310 277541 504620 555082 1110164 1387705 2722661 2775410 5445322 5550820 10890644 13613305 27226610 29949271 54453220 59898542 62621203 119797084 125242406 149746355 250484812 299492710 313106015 598985420 626212030 688833233 1252424060 1377666466 2755332932 2986759117 3444166165 5973518234 6888332330 11947036468 13776664660 14933795585 29867591170 32854350287 59735182340 65708700574 68695459691 131417401148 137390919382 164271751435 274781838764 328543502870 343477298455 657087005740 686954596910 755650056601 1373909193820 1511300113202 3022600226404 3778250283005 7556500566010 15113001132020