Base | Representation |
---|---|
bin | 1000110011011010101… |
… | …1110110101101011111 |
3 | 112110101021020011120221 |
4 | 2030312223312231133 |
5 | 4434220234240221 |
6 | 153251310222211 |
7 | 13632621006553 |
oct | 2146653665537 |
9 | 473337204527 |
10 | 151241321311 |
11 | 59160868233 |
12 | 2538a4b4967 |
13 | 113537b0a02 |
14 | 746a599863 |
15 | 3e02a7d541 |
hex | 2336af6b5f |
151241321311 has 2 divisors, whose sum is σ = 151241321312. Its totient is φ = 151241321310.
The previous prime is 151241321299. The next prime is 151241321327. The reversal of 151241321311 is 113123142151.
It is a weak prime.
It is an emirp because it is prime and its reverse (113123142151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 151241321311 - 29 = 151241320799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151241321411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75620660655 + 75620660656.
It is an arithmetic number, because the mean of its divisors is an integer number (75620660656).
Almost surely, 2151241321311 is an apocalyptic number.
151241321311 is a deficient number, since it is larger than the sum of its proper divisors (1).
151241321311 is an equidigital number, since it uses as much as digits as its factorization.
151241321311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 720, while the sum is 25.
Adding to 151241321311 its reverse (113123142151), we get a palindrome (264364463462).
The spelling of 151241321311 in words is "one hundred fifty-one billion, two hundred forty-one million, three hundred twenty-one thousand, three hundred eleven".
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