Base | Representation |
---|---|
bin | 11100001100001111… |
… | …11001101001111111 |
3 | 1110001210101202110222 |
4 | 32012013321221333 |
5 | 221444042314444 |
6 | 10541502051555 |
7 | 1044030253166 |
oct | 160607715177 |
9 | 43053352428 |
10 | 15135119999 |
11 | 646742073a |
12 | 2b24879bbb |
13 | 157283810c |
14 | a381583dd |
15 | 5d8b04eee |
hex | 3861f9a7f |
15135119999 has 2 divisors, whose sum is σ = 15135120000. Its totient is φ = 15135119998.
The previous prime is 15135119957. The next prime is 15135120001. The reversal of 15135119999 is 99991153151.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15135119999 - 216 = 15135054463 is a prime.
Together with 15135120001, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 15135119999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15135119929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7567559999 + 7567560000.
It is an arithmetic number, because the mean of its divisors is an integer number (7567560000).
Almost surely, 215135119999 is an apocalyptic number.
15135119999 is a deficient number, since it is larger than the sum of its proper divisors (1).
15135119999 is an equidigital number, since it uses as much as digits as its factorization.
15135119999 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 492075, while the sum is 53.
The spelling of 15135119999 in words is "fifteen billion, one hundred thirty-five million, one hundred nineteen thousand, nine hundred ninety-nine".
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