Search a number
-
+
1520323117 is a prime number
BaseRepresentation
bin101101010011110…
…0100101000101101
310220221202102020121
41122213210220231
511103200314432
6410505444541
752450350625
oct13247445055
93827672217
101520323117
11710201295
123651a0751
131b2c897a1
14105cb3885
158d711197
hex5a9e4a2d

1520323117 has 2 divisors, whose sum is σ = 1520323118. Its totient is φ = 1520323116.

The previous prime is 1520323099. The next prime is 1520323177. The reversal of 1520323117 is 7113230251.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 817330921 + 702992196 = 28589^2 + 26514^2 .

It is a cyclic number.

It is not a de Polignac number, because 1520323117 - 211 = 1520321069 is a prime.

It is a super-2 number, since 2×15203231172 = 4622764760169191378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1520323091 and 1520323100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1520323177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760161558 + 760161559.

It is an arithmetic number, because the mean of its divisors is an integer number (760161559).

Almost surely, 21520323117 is an apocalyptic number.

It is an amenable number.

1520323117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1520323117 is an equidigital number, since it uses as much as digits as its factorization.

1520323117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 1520323117 is about 38991.3210471253. The cubic root of 1520323117 is about 1149.8608822261.

Adding to 1520323117 its reverse (7113230251), we get a palindrome (8633553368).

The spelling of 1520323117 in words is "one billion, five hundred twenty million, three hundred twenty-three thousand, one hundred seventeen".