Base | Representation |
---|---|
bin | 1000110110100111100… |
… | …1100001100001001111 |
3 | 112112121011000010112112 |
4 | 2031221321201201033 |
5 | 4443000214330133 |
6 | 153512442254235 |
7 | 13663123164665 |
oct | 2155171414117 |
9 | 475534003475 |
10 | 152100542543 |
11 | 59561877924 |
12 | 2558a1b737b |
13 | 1145c7ca241 |
14 | 750c73cc35 |
15 | 3e53202648 |
hex | 2369e6184f |
152100542543 has 2 divisors, whose sum is σ = 152100542544. Its totient is φ = 152100542542.
The previous prime is 152100542467. The next prime is 152100542557. The reversal of 152100542543 is 345245001251.
152100542543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (345245001251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 152100542543 - 210 = 152100541519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152100542443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76050271271 + 76050271272.
It is an arithmetic number, because the mean of its divisors is an integer number (76050271272).
Almost surely, 2152100542543 is an apocalyptic number.
152100542543 is a deficient number, since it is larger than the sum of its proper divisors (1).
152100542543 is an equidigital number, since it uses as much as digits as its factorization.
152100542543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 152100542543 its reverse (345245001251), we get a palindrome (497345543794).
The spelling of 152100542543 in words is "one hundred fifty-two billion, one hundred million, five hundred forty-two thousand, five hundred forty-three".
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