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152105156471 is a prime number
BaseRepresentation
bin1000110110101000101…
…1000111111101110111
3112112121110200112122202
42031222023013331313
54443002410001341
6153513125215115
713663210332452
oct2155213077567
9475543615582
10152105156471
1159564439394
122558b86149b
1311460754388
14750d1c0499
153e5381479b
hex236a2c7f77

152105156471 has 2 divisors, whose sum is σ = 152105156472. Its totient is φ = 152105156470.

The previous prime is 152105156461. The next prime is 152105156473. The reversal of 152105156471 is 174651501251.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152105156471 is a prime.

It is a super-3 number, since 3×1521051564713 (a number of 35 digits) contains 333 as substring.

Together with 152105156473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152105156473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76052578235 + 76052578236.

It is an arithmetic number, because the mean of its divisors is an integer number (76052578236).

Almost surely, 2152105156471 is an apocalyptic number.

152105156471 is a deficient number, since it is larger than the sum of its proper divisors (1).

152105156471 is an equidigital number, since it uses as much as digits as its factorization.

152105156471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42000, while the sum is 38.

The spelling of 152105156471 in words is "one hundred fifty-two billion, one hundred five million, one hundred fifty-six thousand, four hundred seventy-one".