Base | Representation |
---|---|
bin | 100010101010101011010000… |
… | …010001011101110111110100 |
3 | 201222211122000122100222200200 |
4 | 202222223100101131313310 |
5 | 124441001331242010030 |
6 | 1300134005241240500 |
7 | 44054215433060331 |
oct | 4252532021356764 |
9 | 658748018328620 |
10 | 152466243313140 |
11 | 44642630622029 |
12 | 15124b90493130 |
13 | 670c6747a5413 |
14 | 2991596b89988 |
15 | 1295ee4703d60 |
hex | 8aaad045ddf4 |
152466243313140 has 36 divisors (see below), whose sum is σ = 462480938050404. Its totient is φ = 40657664883456.
The previous prime is 152466243313129. The next prime is 152466243313171. The reversal of 152466243313140 is 41313342664251.
152466243313140 is a `hidden beast` number, since 1 + 5 + 2 + 4 + 6 + 62 + 433 + 13 + 140 = 666.
152466243313140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 110262978381924 + 42203264931216 = 10500618^2 + 6496404^2 .
It is a tau number, because it is divible by the number of its divisors (36).
It is a super-3 number, since 3×1524662433131403 (a number of 44 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 423517342357 + ... + 423517342716.
Almost surely, 2152466243313140 is an apocalyptic number.
152466243313140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
152466243313140 is an abundant number, since it is smaller than the sum of its proper divisors (310014694737264).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
152466243313140 is a wasteful number, since it uses less digits than its factorization.
152466243313140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 847034685088 (or 847034685083 counting only the distinct ones).
The product of its (nonzero) digits is 1244160, while the sum is 45.
Adding to 152466243313140 its reverse (41313342664251), we get a palindrome (193779585977391).
The spelling of 152466243313140 in words is "one hundred fifty-two trillion, four hundred sixty-six billion, two hundred forty-three million, three hundred thirteen thousand, one hundred forty".
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