Base | Representation |
---|---|
bin | 100010101011110000100000… |
… | …100001011010010001100111 |
3 | 202000002201221222100001210002 |
4 | 202223300200201122101213 |
5 | 124443211124123122043 |
6 | 1300232104111251515 |
7 | 44062460241334226 |
oct | 4253604041322147 |
9 | 660081858301702 |
10 | 152540604114023 |
11 | 4467111a32a374 |
12 | 15137483819b9b |
13 | 6716695509908 |
14 | 299500c9d4cbd |
15 | 1297de7aa8bb8 |
hex | 8abc2085a467 |
152540604114023 has 2 divisors, whose sum is σ = 152540604114024. Its totient is φ = 152540604114022.
The previous prime is 152540604113981. The next prime is 152540604114061. The reversal of 152540604114023 is 320411406045251.
It is an a-pointer prime, because the next prime (152540604114061) can be obtained adding 152540604114023 to its sum of digits (38).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 152540604114023 - 210 = 152540604112999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152540604104023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76270302057011 + 76270302057012.
It is an arithmetic number, because the mean of its divisors is an integer number (76270302057012).
Almost surely, 2152540604114023 is an apocalyptic number.
152540604114023 is a deficient number, since it is larger than the sum of its proper divisors (1).
152540604114023 is an equidigital number, since it uses as much as digits as its factorization.
152540604114023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 38.
The spelling of 152540604114023 in words is "one hundred fifty-two trillion, five hundred forty billion, six hundred four million, one hundred fourteen thousand, twenty-three".
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