Base | Representation |
---|---|
bin | 1101111011001110000010… |
… | …0000010101001011000101 |
3 | 2000012201110000012012121012 |
4 | 3132303200200111023011 |
5 | 4001323442140432121 |
6 | 52321442354132005 |
7 | 3140120411534213 |
oct | 336634040251305 |
9 | 60181400165535 |
10 | 15311030014661 |
11 | 497340a316077 |
12 | 1873468b81005 |
13 | 870a93254584 |
14 | 3ad0b489bcb3 |
15 | 1b841d340c5b |
hex | dece08152c5 |
15311030014661 has 2 divisors, whose sum is σ = 15311030014662. Its totient is φ = 15311030014660.
The previous prime is 15311030014649. The next prime is 15311030014697. The reversal of 15311030014661 is 16641003011351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9739985601025 + 5571044413636 = 3120895^2 + 2360306^2 .
It is a cyclic number.
It is not a de Polignac number, because 15311030014661 - 210 = 15311030013637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15311030014561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7655515007330 + 7655515007331.
It is an arithmetic number, because the mean of its divisors is an integer number (7655515007331).
Almost surely, 215311030014661 is an apocalyptic number.
It is an amenable number.
15311030014661 is a deficient number, since it is larger than the sum of its proper divisors (1).
15311030014661 is an equidigital number, since it uses as much as digits as its factorization.
15311030014661 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 32.
The spelling of 15311030014661 in words is "fifteen trillion, three hundred eleven billion, thirty million, fourteen thousand, six hundred sixty-one".
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