153131404052130 has 64 divisors (see below), whose sum is σ = 420020513365248. Its totient is φ = 35001218119680.

The previous prime is 153131404052119. The next prime is 153131404052153. The reversal of 153131404052130 is 31250404131351.

It is a junction number, because it is equal to n+sod(n) for n = 153131404052091 and 153131404052100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 28317354 + ... + 33288666.

It is an arithmetic number, because the mean of its divisors is an integer number (6562820521332).

Almost surely, 2^{153131404052130} is an apocalyptic number.

153131404052130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

153131404052130 is an abundant number, since it is smaller than the sum of its proper divisors (266889109313118).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

153131404052130 is a wasteful number, since it uses less digits than its factorization.

153131404052130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5118011.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 153131404052130 its reverse (31250404131351), we get a palindrome (184381808183481).

The spelling of 153131404052130 in words is "one hundred fifty-three trillion, one hundred thirty-one billion, four hundred four million, fifty-two thousand, one hundred thirty".