Base | Representation |
---|---|
bin | 1101111011010110100010… |
… | …1010100111011101110000 |
3 | 2000012221100012200122011212 |
4 | 3132311220222213131300 |
5 | 4001343131442144100 |
6 | 52322501200455252 |
7 | 3140231130564014 |
oct | 336655052473560 |
9 | 60187305618155 |
10 | 15313314412400 |
11 | 497438184a994 |
12 | 18739a601a528 |
13 | 8710685c5c04 |
14 | 3ad250028544 |
15 | 1b8503b7e635 |
hex | ded68aa7770 |
15313314412400 has 120 divisors (see below), whose sum is σ = 38393041911264. Its totient is φ = 5858514534400.
The previous prime is 15313314412399. The next prime is 15313314412421. The reversal of 15313314412400 is 421441331351.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 120649772 + ... + 120776628.
Almost surely, 215313314412400 is an apocalyptic number.
15313314412400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 15313314412400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19196520955632).
15313314412400 is an abundant number, since it is smaller than the sum of its proper divisors (23079727498864).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15313314412400 is a wasteful number, since it uses less digits than its factorization.
15313314412400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 140019 (or 140008 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 15313314412400 its reverse (421441331351), we get a palindrome (15734755743751).
The spelling of 15313314412400 in words is "fifteen trillion, three hundred thirteen billion, three hundred fourteen million, four hundred twelve thousand, four hundred".
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