1531401413441 has 2 divisors, whose sum is σ = 1531401413442. Its totient is φ = 1531401413440.

The previous prime is 1531401413419. The next prime is 1531401413453. The reversal of 1531401413441 is 1443141041351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 989469867841 + 541931545600 = 994721^2 + 736160^2 .

It is an emirp because it is prime and its reverse (1443141041351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1531401413441 - 2¹⁸ = 1531401151297 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1531401413398 and 1531401413407.

It is not a weakly prime, because it can be changed into another prime (1531401413471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765700706720 + 765700706721.

It is an arithmetic number, because the mean of its divisors is an integer number (765700706721).

Almost surely, 2^{1531401413441} is an apocalyptic number.

It is an amenable number.

1531401413441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1531401413441 is an equidigital number, since it uses as much as digits as its factorization.

1531401413441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 1531401413441 its reverse (1443141041351), we get a palindrome (2974542454792).

The spelling of 1531401413441 in words is "one trillion, five hundred thirty-one billion, four hundred one million, four hundred thirteen thousand, four hundred forty-one".