Base | Representation |
---|---|
bin | 10110010010001110101… |
… | …000110010001101000000 |
3 | 12102101210222221012221011 |
4 | 112102032220302031000 |
5 | 200042302230212230 |
6 | 3131303251010304 |
7 | 215432361144613 |
oct | 26221650621500 |
9 | 5371728835834 |
10 | 1531401413440 |
11 | 5405111a1048 |
12 | 208967299994 |
13 | b1544c33612 |
14 | 54197c7417a |
15 | 29c7e046e2a |
hex | 1648ea32340 |
1531401413440 has 56 divisors (see below), whose sum is σ = 3708457282080. Its totient is φ = 602178175488.
The previous prime is 1531401413419. The next prime is 1531401413441. The reversal of 1531401413440 is 443141041351.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1531401413441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40537302 + ... + 40575061.
Almost surely, 21531401413440 is an apocalyptic number.
1531401413440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1531401413440 is an abundant number, since it is smaller than the sum of its proper divisors (2177055868640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1531401413440 is an equidigital number, since it uses as much as digits as its factorization.
1531401413440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81112439 (or 81112429 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1531401413440 its reverse (443141041351), we get a palindrome (1974542454791).
The spelling of 1531401413440 in words is "one trillion, five hundred thirty-one billion, four hundred one million, four hundred thirteen thousand, four hundred forty".
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