Base | Representation |
---|---|
bin | 10110011100100110110… |
… | …100000110101101100010 |
3 | 12110110120120112020210200 |
4 | 112130212310012231202 |
5 | 200233112334434300 |
6 | 3140345105010030 |
7 | 216305455336041 |
oct | 26344664065542 |
9 | 5413516466720 |
10 | 1542544452450 |
11 | 54520a1471a1 |
12 | 20ab57023916 |
13 | b25cc690621 |
14 | 54933b3a558 |
15 | 2a1d243d200 |
hex | 16726d06b62 |
1542544452450 has 144 divisors (see below), whose sum is σ = 4164699442176. Its totient is φ = 409324492800.
The previous prime is 1542544452373. The next prime is 1542544452487. The reversal of 1542544452450 is 542544452451.
1542544452450 is a `hidden beast` number, since 1 + 5 + 4 + 2 + 544 + 4 + 52 + 4 + 50 = 666.
It is a super-2 number, since 2×15425444524502 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1542544452396 and 1542544452405.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 105235522 + ... + 105250178.
It is an arithmetic number, because the mean of its divisors is an integer number (28921523904).
Almost surely, 21542544452450 is an apocalyptic number.
1542544452450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1542544452450, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2082349721088).
1542544452450 is an abundant number, since it is smaller than the sum of its proper divisors (2622154989726).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1542544452450 is a wasteful number, since it uses less digits than its factorization.
1542544452450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15809 (or 15801 counting only the distinct ones).
The product of its (nonzero) digits is 2560000, while the sum is 45.
Subtracting from 1542544452450 its reverse (542544452451), we obtain a palindrome (999999999999).
The spelling of 1542544452450 in words is "one trillion, five hundred forty-two billion, five hundred forty-four million, four hundred fifty-two thousand, four hundred fifty".
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