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155343407 is a prime number
BaseRepresentation
bin10010100001001…
…01101000101111
3101211022021002112
421100211220233
5304231442112
623225314235
73564253142
oct1120455057
9354267075
10155343407
117a76188a
124403597b
132625009b
14168ba059
15d987a22
hex9425a2f

155343407 has 2 divisors, whose sum is σ = 155343408. Its totient is φ = 155343406.

The previous prime is 155343389. The next prime is 155343439. The reversal of 155343407 is 704343551.

It is an a-pointer prime, because the next prime (155343439) can be obtained adding 155343407 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 155343407 - 214 = 155327023 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (155343457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77671703 + 77671704.

It is an arithmetic number, because the mean of its divisors is an integer number (77671704).

Almost surely, 2155343407 is an apocalyptic number.

155343407 is a deficient number, since it is larger than the sum of its proper divisors (1).

155343407 is an equidigital number, since it uses as much as digits as its factorization.

155343407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 32.

The square root of 155343407 is about 12463.6835245444. The cubic root of 155343407 is about 537.5649470466.

Adding to 155343407 its reverse (704343551), we get a palindrome (859686958).

The spelling of 155343407 in words is "one hundred fifty-five million, three hundred forty-three thousand, four hundred seven".