Base | Representation |
---|---|
bin | 1110100011111110101011… |
… | …0101000011011011010111 |
3 | 2002200122220211111220220102 |
4 | 3220333222311003123113 |
5 | 4044312101404412112 |
6 | 54015252023324315 |
7 | 3241530342002042 |
oct | 350775265033327 |
9 | 62618824456812 |
10 | 16011282888407 |
11 | 511338a860534 |
12 | 19671162b069b |
13 | 8c1b1bbcbc41 |
14 | 3d4d435c9c59 |
15 | 1cb7546e8bc2 |
hex | e8fead436d7 |
16011282888407 has 2 divisors, whose sum is σ = 16011282888408. Its totient is φ = 16011282888406.
The previous prime is 16011282888397. The next prime is 16011282888409. The reversal of 16011282888407 is 70488828211061.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16011282888407 is a prime.
It is a super-2 number, since 2×160112828884072 (a number of 27 digits) contains 22 as substring.
Together with 16011282888409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16011282888409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8005641444203 + 8005641444204.
It is an arithmetic number, because the mean of its divisors is an integer number (8005641444204).
Almost surely, 216011282888407 is an apocalyptic number.
16011282888407 is a deficient number, since it is larger than the sum of its proper divisors (1).
16011282888407 is an equidigital number, since it uses as much as digits as its factorization.
16011282888407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2752512, while the sum is 56.
The spelling of 16011282888407 in words is "sixteen trillion, eleven billion, two hundred eighty-two million, eight hundred eighty-eight thousand, four hundred seven".
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