Base | Representation |
---|---|
bin | 11110000000001000… |
… | …01000010100001111 |
3 | 1112120112120001021022 |
4 | 33000010020110033 |
5 | 230441421204444 |
6 | 11222145224355 |
7 | 1110103011626 |
oct | 170004102417 |
9 | 45515501238 |
10 | 16107209999 |
11 | 6916111301 |
12 | 31563320bb |
13 | 16990526ba |
14 | acb2bc6bd |
15 | 6441219ee |
hex | 3c010850f |
16107209999 has 2 divisors, whose sum is σ = 16107210000. Its totient is φ = 16107209998.
The previous prime is 16107209983. The next prime is 16107210001. The reversal of 16107209999 is 99990270161.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16107209999 - 24 = 16107209983 is a prime.
Together with 16107210001, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16107209999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16107203999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8053604999 + 8053605000.
It is an arithmetic number, because the mean of its divisors is an integer number (8053605000).
Almost surely, 216107209999 is an apocalyptic number.
16107209999 is a deficient number, since it is larger than the sum of its proper divisors (1).
16107209999 is an equidigital number, since it uses as much as digits as its factorization.
16107209999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 551124, while the sum is 53.
The spelling of 16107209999 in words is "sixteen billion, one hundred seven million, two hundred nine thousand, nine hundred ninety-nine".
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