Base | Representation |
---|---|
bin | 100100101000010101000111… |
… | …110000001110011100010110 |
3 | 210010102010011220001222111000 |
4 | 210220111013300032130112 |
5 | 132103440104311130240 |
6 | 1330344501032124130 |
7 | 45635113144021206 |
oct | 4450250760163426 |
9 | 703363156058430 |
10 | 161101132130070 |
11 | 4737167420a360 |
12 | 1609a58b236646 |
13 | 6bb7a051bca42 |
14 | 2bad49d116406 |
15 | 1395924404430 |
hex | 928547c0e716 |
161101132130070 has 128 divisors (see below), whose sum is σ = 468668728442880. Its totient is φ = 39053912451840.
The previous prime is 161101132129999. The next prime is 161101132130089. The reversal of 161101132130070 is 70031231101161.
161101132130070 is a `hidden beast` number, since 1 + 61 + 101 + 132 + 1 + 300 + 70 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 131904619 + ... + 133120361.
It is an arithmetic number, because the mean of its divisors is an integer number (3661474440960).
Almost surely, 2161101132130070 is an apocalyptic number.
161101132130070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
161101132130070 is an abundant number, since it is smaller than the sum of its proper divisors (307567596312810).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
161101132130070 is a wasteful number, since it uses less digits than its factorization.
161101132130070 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1260387 (or 1260381 counting only the distinct ones).
The product of its (nonzero) digits is 756, while the sum is 27.
The spelling of 161101132130070 in words is "one hundred sixty-one trillion, one hundred one billion, one hundred thirty-two million, one hundred thirty thousand, seventy".
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