Base | Representation |
---|---|
bin | 11110000000110101… |
… | …10000001011001111 |
3 | 1112120221201100021221 |
4 | 33000122300023033 |
5 | 230444430443211 |
6 | 11222520304211 |
7 | 1110204301543 |
oct | 170032601317 |
9 | 45527640257 |
10 | 16113140431 |
11 | 69194a1993 |
12 | 3158312067 |
13 | 169a34ab2b |
14 | acbdc3a23 |
15 | 6448e3c71 |
hex | 3c06b02cf |
16113140431 has 2 divisors, whose sum is σ = 16113140432. Its totient is φ = 16113140430.
The previous prime is 16113140371. The next prime is 16113140453. The reversal of 16113140431 is 13404131161.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16113140431 - 29 = 16113139919 is a prime.
It is a super-2 number, since 2×161131404312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16113140396 and 16113140405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16113140231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8056570215 + 8056570216.
It is an arithmetic number, because the mean of its divisors is an integer number (8056570216).
Almost surely, 216113140431 is an apocalyptic number.
16113140431 is a deficient number, since it is larger than the sum of its proper divisors (1).
16113140431 is an equidigital number, since it uses as much as digits as its factorization.
16113140431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 16113140431 its reverse (13404131161), we get a palindrome (29517271592).
The spelling of 16113140431 in words is "sixteen billion, one hundred thirteen million, one hundred forty thousand, four hundred thirty-one".
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