Base | Representation |
---|---|
bin | 1001011001000000111… |
… | …1001101001001001010 |
3 | 120102102121210212122220 |
4 | 2112100033031021022 |
5 | 10120402411220200 |
6 | 202040552554510 |
7 | 14440666531653 |
oct | 2262017151112 |
9 | 512377725586 |
10 | 161333695050 |
11 | 6246a734a80 |
12 | 273263b2a36 |
13 | 122a16716a8 |
14 | 7b46ac652a |
15 | 42e3ad64a0 |
hex | 25903cd24a |
161333695050 has 48 divisors (see below), whose sum is σ = 436480983072. Its totient is φ = 39111198400.
The previous prime is 161333695043. The next prime is 161333695051. The reversal of 161333695050 is 50596333161.
It is a super-2 number, since 2×1613336950502 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 161333694993 and 161333695011.
It is not an unprimeable number, because it can be changed into a prime (161333695051) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 48887349 + ... + 48890648.
It is an arithmetic number, because the mean of its divisors is an integer number (9093353814).
Almost surely, 2161333695050 is an apocalyptic number.
161333695050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
161333695050 is an abundant number, since it is smaller than the sum of its proper divisors (275147288022).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
161333695050 is a wasteful number, since it uses less digits than its factorization.
161333695050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97778023 (or 97778018 counting only the distinct ones).
The product of its (nonzero) digits is 218700, while the sum is 42.
The spelling of 161333695050 in words is "one hundred sixty-one billion, three hundred thirty-three million, six hundred ninety-five thousand, fifty".
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