Base | Representation |
---|---|
bin | 10011001111001… |
… | …11010000011001 |
3 | 102020122220212002 |
4 | 21213213100121 |
5 | 312303114403 |
6 | 24002530345 |
7 | 3666462512 |
oct | 1147472031 |
9 | 366586762 |
10 | 161379353 |
11 | 83104773 |
12 | 460669b5 |
13 | 27584555 |
14 | 1760ba09 |
15 | e27b188 |
hex | 99e7419 |
161379353 has 2 divisors, whose sum is σ = 161379354. Its totient is φ = 161379352.
The previous prime is 161379347. The next prime is 161379359. The reversal of 161379353 is 353973161.
161379353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (161379347) and next prime (161379359).
It can be written as a sum of positive squares in only one way, i.e., 157427209 + 3952144 = 12547^2 + 1988^2 .
It is an emirp because it is prime and its reverse (353973161) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 161379353 - 212 = 161375257 is a prime.
It is a Sophie Germain prime.
It is a Chen prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (161379359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80689676 + 80689677.
It is an arithmetic number, because the mean of its divisors is an integer number (80689677).
Almost surely, 2161379353 is an apocalyptic number.
It is an amenable number.
161379353 is a deficient number, since it is larger than the sum of its proper divisors (1).
161379353 is an equidigital number, since it uses as much as digits as its factorization.
161379353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51030, while the sum is 38.
The square root of 161379353 is about 12703.5173475695. The cubic root of 161379353 is about 544.4391199705.
The spelling of 161379353 in words is "one hundred sixty-one million, three hundred seventy-nine thousand, three hundred fifty-three".
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