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16181972154431 is a prime number
BaseRepresentation
bin1110101101111010100010…
…1100111011100000111111
32010021222111110111001020222
43223132220230323200333
54110111134332420211
654225521222531555
73260052232554116
oct353365054734077
963258443431228
1016181972154431
115179810466446
121994211896bbb
13904c518a7735
143dd2d6a04c7d
151d0de47e61db
hexeb7a8b3b83f

16181972154431 has 2 divisors, whose sum is σ = 16181972154432. Its totient is φ = 16181972154430.

The previous prime is 16181972154427. The next prime is 16181972154433. The reversal of 16181972154431 is 13445127918161.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 16181972154431 - 22 = 16181972154427 is a prime.

It is a super-3 number, since 3×161819721544313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 16181972154433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16181972154433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8090986077215 + 8090986077216.

It is an arithmetic number, because the mean of its divisors is an integer number (8090986077216).

Almost surely, 216181972154431 is an apocalyptic number.

16181972154431 is a deficient number, since it is larger than the sum of its proper divisors (1).

16181972154431 is an equidigital number, since it uses as much as digits as its factorization.

16181972154431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1451520, while the sum is 53.

The spelling of 16181972154431 in words is "sixteen trillion, one hundred eighty-one billion, nine hundred seventy-two million, one hundred fifty-four thousand, four hundred thirty-one".