Base | Representation |
---|---|
bin | 10111101001011101100… |
… | …111101000110010010010 |
3 | 12202100120210201120000020 |
4 | 113221131213220302102 |
5 | 203111114441402100 |
6 | 3242313541404310 |
7 | 225256464501642 |
oct | 27513547506222 |
9 | 5670523646006 |
10 | 1625068309650 |
11 | 577207771575 |
12 | 222b48109696 |
13 | ba321658866 |
14 | 58921b76522 |
15 | 2c41229b5a0 |
hex | 17a5d9e8c92 |
1625068309650 has 48 divisors (see below), whose sum is σ = 4034839682304. Its totient is φ = 432849369280.
The previous prime is 1625068309643. The next prime is 1625068309693. The reversal of 1625068309650 is 569038605261.
It is a super-2 number, since 2×16250683096502 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1625068309593 and 1625068309602.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6147369 + ... + 6406268.
It is an arithmetic number, because the mean of its divisors is an integer number (84059160048).
Almost surely, 21625068309650 is an apocalyptic number.
1625068309650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1625068309650 is an abundant number, since it is smaller than the sum of its proper divisors (2409771372654).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1625068309650 is a wasteful number, since it uses less digits than its factorization.
1625068309650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12554515 (or 12554510 counting only the distinct ones).
The product of its (nonzero) digits is 2332800, while the sum is 51.
The spelling of 1625068309650 in words is "one trillion, six hundred twenty-five billion, sixty-eight million, three hundred nine thousand, six hundred fifty".
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