Base | Representation |
---|---|
bin | 1110110101100111001101… |
… | …1011000100001100111111 |
3 | 2010202121212012101202111212 |
4 | 3231121303123010030333 |
5 | 4114243011344441101 |
6 | 54410352241435035 |
7 | 3302443431136046 |
oct | 355316333041477 |
9 | 63677765352455 |
10 | 16314222265151 |
11 | 521a906181008 |
12 | 19b598003ba7b |
13 | 9145699a7515 |
14 | 405880c7355d |
15 | 1d4584e741bb |
hex | ed6736c433f |
16314222265151 has 2 divisors, whose sum is σ = 16314222265152. Its totient is φ = 16314222265150.
The previous prime is 16314222265141. The next prime is 16314222265153. The reversal of 16314222265151 is 15156222241361.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16314222265151 is a prime.
Together with 16314222265153, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 16314222265099 and 16314222265108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16314222265153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8157111132575 + 8157111132576.
It is an arithmetic number, because the mean of its divisors is an integer number (8157111132576).
Almost surely, 216314222265151 is an apocalyptic number.
16314222265151 is a deficient number, since it is larger than the sum of its proper divisors (1).
16314222265151 is an equidigital number, since it uses as much as digits as its factorization.
16314222265151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 172800, while the sum is 41.
The spelling of 16314222265151 in words is "sixteen trillion, three hundred fourteen billion, two hundred twenty-two million, two hundred sixty-five thousand, one hundred fifty-one".
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