Base | Representation |
---|---|
bin | 1111001000110101010100… |
… | …0001111001001011100000 |
3 | 2011221012011120210010201022 |
4 | 3302031111001321023200 |
5 | 4140200240224103322 |
6 | 55222202044425012 |
7 | 3335343235504346 |
oct | 362152501711340 |
9 | 64835146703638 |
10 | 16644424831712 |
11 | 5337951997617 |
12 | 1a49974248168 |
13 | 939740b43792 |
14 | 4178472ad996 |
15 | 1dce5de21942 |
hex | f23550792e0 |
16644424831712 has 48 divisors (see below), whose sum is σ = 33779461998240. Its totient is φ = 8067186160128.
The previous prime is 16644424831663. The next prime is 16644424831733. The reversal of 16644424831712 is 21713842444661.
It is a super-3 number, since 3×166444248317123 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25811228 + ... + 26448219.
It is an arithmetic number, because the mean of its divisors is an integer number (703738791630).
Almost surely, 216644424831712 is an apocalyptic number.
It is an amenable number.
16644424831712 is an abundant number, since it is smaller than the sum of its proper divisors (17135037166528).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
16644424831712 is a wasteful number, since it uses less digits than its factorization.
16644424831712 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52259763 (or 52259755 counting only the distinct ones).
The product of its digits is 6193152, while the sum is 53.
The spelling of 16644424831712 in words is "sixteen trillion, six hundred forty-four billion, four hundred twenty-four million, eight hundred thirty-one thousand, seven hundred twelve".
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