Base | Representation |
---|---|
bin | 11001000010000000011… |
… | …011000101011111010111 |
3 | 20002102222121201011022012 |
4 | 121002000123011133113 |
5 | 211140322211034143 |
6 | 3354115550054435 |
7 | 235163465344661 |
oct | 31020033053727 |
9 | 6072877634265 |
10 | 1720141502423 |
11 | 603565041463 |
12 | 23945baaa41b |
13 | c6293525546 |
14 | 5d380749531 |
15 | 2eb28bdb418 |
hex | 190806c57d7 |
1720141502423 has 2 divisors, whose sum is σ = 1720141502424. Its totient is φ = 1720141502422.
The previous prime is 1720141502407. The next prime is 1720141502441. The reversal of 1720141502423 is 3242051410271.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1720141502423 - 24 = 1720141502407 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1720141502423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1720141502473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 860070751211 + 860070751212.
It is an arithmetic number, because the mean of its divisors is an integer number (860070751212).
Almost surely, 21720141502423 is an apocalyptic number.
1720141502423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1720141502423 is an equidigital number, since it uses as much as digits as its factorization.
1720141502423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 1720141502423 its reverse (3242051410271), we get a palindrome (4962192912694).
The spelling of 1720141502423 in words is "one trillion, seven hundred twenty billion, one hundred forty-one million, five hundred two thousand, four hundred twenty-three".
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