Base | Representation |
---|---|
bin | 10000101111111001… |
… | …000000111011010101 |
3 | 1201102021211112202102 |
4 | 100233321000323111 |
5 | 243312214004331 |
6 | 12132245251445 |
7 | 1204433622224 |
oct | 205771007325 |
9 | 51367745672 |
10 | 17983344341 |
11 | 7699146856 |
12 | 359a703b85 |
13 | 190794b471 |
14 | c28532cbb |
15 | 703bb84cb |
hex | 42fe40ed5 |
17983344341 has 2 divisors, whose sum is σ = 17983344342. Its totient is φ = 17983344340.
The previous prime is 17983344331. The next prime is 17983344343. The reversal of 17983344341 is 14344338971.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13707492241 + 4275852100 = 117079^2 + 65390^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-17983344341 is a prime.
Together with 17983344343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17983344343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8991672170 + 8991672171.
It is an arithmetic number, because the mean of its divisors is an integer number (8991672171).
Almost surely, 217983344341 is an apocalyptic number.
It is an amenable number.
17983344341 is a deficient number, since it is larger than the sum of its proper divisors (1).
17983344341 is an equidigital number, since it uses as much as digits as its factorization.
17983344341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 870912, while the sum is 47.
The spelling of 17983344341 in words is "seventeen billion, nine hundred eighty-three million, three hundred forty-four thousand, three hundred forty-one".
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