Base | Representation |
---|---|
bin | 1000110101000101011111… |
… | …10100100010101111111101 |
3 | 2112202011121111110112020022 |
4 | 10122202233310202233331 |
5 | 10021103340200331131 |
6 | 105143402520101525 |
7 | 4042526404423034 |
oct | 432425764425775 |
9 | 75664544415208 |
10 | 19416201964541 |
11 | 6206401914288 |
12 | 2216ba69048a5 |
13 | aaac2b203cc5 |
14 | 4b1a6babd71b |
15 | 23a0d760537b |
hex | 11a8afd22bfd |
19416201964541 has 2 divisors, whose sum is σ = 19416201964542. Its totient is φ = 19416201964540.
The previous prime is 19416201964487. The next prime is 19416201964543. The reversal of 19416201964541 is 14546910261491.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14936841362041 + 4479360602500 = 3864821^2 + 2116450^2 .
It is a cyclic number.
It is not a de Polignac number, because 19416201964541 - 210 = 19416201963517 is a prime.
Together with 19416201964543, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19416201964543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9708100982270 + 9708100982271.
It is an arithmetic number, because the mean of its divisors is an integer number (9708100982271).
Almost surely, 219416201964541 is an apocalyptic number.
It is an amenable number.
19416201964541 is a deficient number, since it is larger than the sum of its proper divisors (1).
19416201964541 is an equidigital number, since it uses as much as digits as its factorization.
19416201964541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 53.
The spelling of 19416201964541 in words is "nineteen trillion, four hundred sixteen billion, two hundred one million, nine hundred sixty-four thousand, five hundred forty-one".
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