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1987260051943 is a prime number
BaseRepresentation
bin11100111010110001111…
…011011111000111100111
321000222110120101102201001
4130322301323133013213
5230024402033130233
64120533515414131
7263401104506245
oct34726173370747
97028416342631
101987260051943
116a68795452a1
12281189454347
1311552301447a
146c280899795
1536a5e7e827d
hex1ceb1edf1e7

1987260051943 has 2 divisors, whose sum is σ = 1987260051944. Its totient is φ = 1987260051942.

The previous prime is 1987260051941. The next prime is 1987260051961. The reversal of 1987260051943 is 3491500627891.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1987260051943 - 21 = 1987260051941 is a prime.

Together with 1987260051941, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1987260051941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 993630025971 + 993630025972.

It is an arithmetic number, because the mean of its divisors is an integer number (993630025972).

It is a 2-persistent number, because it is pandigital, and so is 2⋅1987260051943 = 3974520103886, but 3⋅1987260051943 = 5961780155829 is not.

Almost surely, 21987260051943 is an apocalyptic number.

1987260051943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1987260051943 is an equidigital number, since it uses as much as digits as its factorization.

1987260051943 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 1987260051943 in words is "one trillion, nine hundred eighty-seven billion, two hundred sixty million, fifty-one thousand, nine hundred forty-three".