Base | Representation |
---|---|
bin | 100110000011… |
… | …0101100000101 |
3 | 1101112120201112 |
4 | 1030012230011 |
5 | 20101402331 |
6 | 1551334405 |
7 | 331401155 |
oct | 114065405 |
9 | 41476645 |
10 | 19950341 |
11 | 10296a94 |
12 | 6821405 |
13 | 4196948 |
14 | 2914765 |
15 | 1b4132b |
hex | 1306b05 |
19950341 has 2 divisors, whose sum is σ = 19950342. Its totient is φ = 19950340.
The previous prime is 19950331. The next prime is 19950373. The reversal of 19950341 is 14305991.
It is an a-pointer prime, because the next prime (19950373) can be obtained adding 19950341 to its sum of digits (32).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19838116 + 112225 = 4454^2 + 335^2 .
It is a cyclic number.
It is not a de Polignac number, because 19950341 - 214 = 19933957 is a prime.
It is a super-2 number, since 2×199503412 = 796032212032562, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 19950298 and 19950307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19950311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9975170 + 9975171.
It is an arithmetic number, because the mean of its divisors is an integer number (9975171).
Almost surely, 219950341 is an apocalyptic number.
It is an amenable number.
19950341 is a deficient number, since it is larger than the sum of its proper divisors (1).
19950341 is an equidigital number, since it uses as much as digits as its factorization.
19950341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 32.
The square root of 19950341 is about 4466.5804593671. The cubic root of 19950341 is about 271.2169166897.
The spelling of 19950341 in words is "nineteen million, nine hundred fifty thousand, three hundred forty-one".
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