Base | Representation |
---|---|
bin | 10010100110100111… |
… | …111110110100010001 |
3 | 1220120010011211102201 |
4 | 102212213332310101 |
5 | 311402143233303 |
6 | 13102045243201 |
7 | 1305002553232 |
oct | 224647766421 |
9 | 56503154381 |
10 | 19975367953 |
11 | 8520635662 |
12 | 3a55863501 |
13 | 1b64562068 |
14 | d76d13089 |
15 | 7bda0281d |
hex | 4a69fed11 |
19975367953 has 2 divisors, whose sum is σ = 19975367954. Its totient is φ = 19975367952.
The previous prime is 19975367879. The next prime is 19975367987. The reversal of 19975367953 is 35976357991.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14283118144 + 5692249809 = 119512^2 + 75447^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19975367953 is a prime.
It is not a weakly prime, because it can be changed into another prime (19975367053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9987683976 + 9987683977.
It is an arithmetic number, because the mean of its divisors is an integer number (9987683977).
Almost surely, 219975367953 is an apocalyptic number.
It is an amenable number.
19975367953 is a deficient number, since it is larger than the sum of its proper divisors (1).
19975367953 is an equidigital number, since it uses as much as digits as its factorization.
19975367953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48223350, while the sum is 64.
The spelling of 19975367953 in words is "nineteen billion, nine hundred seventy-five million, three hundred sixty-seven thousand, nine hundred fifty-three".
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