Base | Representation |
---|---|
bin | 10010100111101010… |
… | …101010101111111000 |
3 | 1220121100001222110201 |
4 | 102213222222233320 |
5 | 311421132140100 |
6 | 13103512051544 |
7 | 1305304262446 |
oct | 224752525770 |
9 | 56540058421 |
10 | 19992849400 |
11 | 852a495737 |
12 | 3a5b693bb4 |
13 | 1b68073004 |
14 | d79383b96 |
15 | 7c030736a |
hex | 4a7aaabf8 |
19992849400 has 48 divisors (see below), whose sum is σ = 48086263800. Its totient is φ = 7721374080.
The previous prime is 19992849347. The next prime is 19992849403. The reversal of 19992849400 is 494829991.
It is a super-3 number, since 3×199928494003 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19992849403) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1717722 + ... + 1729321.
Almost surely, 219992849400 is an apocalyptic number.
19992849400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
19992849400 is an abundant number, since it is smaller than the sum of its proper divisors (28093414400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
19992849400 is a wasteful number, since it uses less digits than its factorization.
19992849400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3447088 (or 3447079 counting only the distinct ones).
The product of its (nonzero) digits is 1679616, while the sum is 55.
The spelling of 19992849400 in words is "nineteen billion, nine hundred ninety-two million, eight hundred forty-nine thousand, four hundred".
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