19999225007 has 2 divisors, whose sum is σ = 19999225008. Its totient is φ = 19999225006.

The previous prime is 19999225003. The next prime is 19999225009. The reversal of 19999225007 is 70052299991.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 19999225007 - 2² = 19999225003 is a prime.

It is a super-3 number, since 3×19999225007³ (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 19999225009, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 19999225007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (19999225003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9999612503 + 9999612504.

It is an arithmetic number, because the mean of its divisors is an integer number (9999612504).

Almost surely, 2^19999225007 is an apocalyptic number.

19999225007 is a deficient number, since it is larger than the sum of its proper divisors (1).

19999225007 is an equidigital number, since it uses as much as digits as its factorization.

19999225007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 918540, while the sum is 53.

The spelling of 19999225007 in words is "nineteen billion, nine hundred ninety-nine million, two hundred twenty-five thousand, seven".