Base | Representation |
---|---|
bin | 101101011110100011000011… |
… | …001001101000001110010100 |
3 | 222020011220011011111112222221 |
4 | 231132203003021220032110 |
5 | 202203441131121340200 |
6 | 1545215532230032124 |
7 | 60062224513256530 |
oct | 5536430311501624 |
9 | 866156134445887 |
10 | 200011311121300 |
11 | 58803358931188 |
12 | 1a5236474a8644 |
13 | 877aca77a9373 |
14 | 3756855d60bc0 |
15 | 181cb470d791a |
hex | b5e8c3268394 |
200011311121300 has 36 divisors (see below), whose sum is σ = 496028051582560. Its totient is φ = 68575306669920.
The previous prime is 200011311121291. The next prime is 200011311121313. The reversal of 200011311121300 is 3121113110002.
It is a happy number.
It is a super-2 number, since 2×2000113111213002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 142865221530 + ... + 142865222929.
Almost surely, 2200011311121300 is an apocalyptic number.
200011311121300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
200011311121300 is an abundant number, since it is smaller than the sum of its proper divisors (296016740461260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200011311121300 is a wasteful number, since it uses less digits than its factorization.
200011311121300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 285730444480 (or 285730444473 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 200011311121300 its reverse (3121113110002), we get a palindrome (203132424231302).
The spelling of 200011311121300 in words is "two hundred trillion, eleven billion, three hundred eleven million, one hundred twenty-one thousand, three hundred".
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