Base | Representation |
---|---|
bin | 101101011110100011000011… |
… | …001001101011000101001000 |
3 | 222020011220011011112011001021 |
4 | 231132203003021223011020 |
5 | 202203441131122224000 |
6 | 1545215532230202224 |
7 | 60062224513335613 |
oct | 5536430311530510 |
9 | 866156134464037 |
10 | 200011311133000 |
11 | 58803358939a54 |
12 | 1a5236474b3374 |
13 | 877aca77b17a3 |
14 | 3756855d6517a |
15 | 181cb470db11a |
hex | b5e8c326b148 |
200011311133000 has 64 divisors (see below), whose sum is σ = 475699033246320. Its totient is φ = 78692974848000.
The previous prime is 200011311132967. The next prime is 200011311133069. The reversal of 200011311133000 is 331113110002.
It can be written as a sum of positive squares in 8 ways, for example, as 19106497725604 + 180904813407396 = 4371098^2 + 13450086^2 .
It is a super-2 number, since 2×2000113111330002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1639375977 + ... + 1639497976.
Almost surely, 2200011311133000 is an apocalyptic number.
200011311133000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
200011311133000 is an abundant number, since it is smaller than the sum of its proper divisors (275687722113320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200011311133000 is a wasteful number, since it uses less digits than its factorization.
200011311133000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3278874035 (or 3278874021 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 200011311133000 its reverse (331113110002), we get a palindrome (200342424243002).
The spelling of 200011311133000 in words is "two hundred trillion, eleven billion, three hundred eleven million, one hundred thirty-three thousand".
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