Base | Representation |
---|---|
bin | 101101011110101101001000… |
… | …101000001010101110001111 |
3 | 222020012221002212202111111112 |
4 | 231132231020220022232033 |
5 | 202204130320422244442 |
6 | 1545224522555442235 |
7 | 60063060051010661 |
oct | 5536551050125617 |
9 | 866187085674445 |
10 | 200022140431247 |
11 | 58807a05786012 |
12 | 1a52576a15637b |
13 | 877c01223c584 |
14 | 37571a22bc531 |
15 | 181d07cbac082 |
hex | b5eb48a0ab8f |
200022140431247 has 2 divisors, whose sum is σ = 200022140431248. Its totient is φ = 200022140431246.
The previous prime is 200022140431159. The next prime is 200022140431249. The reversal of 200022140431247 is 742134041220002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200022140431247 - 210 = 200022140430223 is a prime.
Together with 200022140431249, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200022140431249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100011070215623 + 100011070215624.
It is an arithmetic number, because the mean of its divisors is an integer number (100011070215624).
Almost surely, 2200022140431247 is an apocalyptic number.
200022140431247 is a deficient number, since it is larger than the sum of its proper divisors (1).
200022140431247 is an equidigital number, since it uses as much as digits as its factorization.
200022140431247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 200022140431247 its reverse (742134041220002), we get a palindrome (942156181651249).
The spelling of 200022140431247 in words is "two hundred trillion, twenty-two billion, one hundred forty million, four hundred thirty-one thousand, two hundred forty-seven".
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